Quiz Discussion

200 ÷ 25 × 4 + 12 - 3 = ?

Course Name: Quantitative Aptitude

  • 1] 35
  • 2] 40
  • 3] 30
  • 4] 41
  • 5] 50
Solution
No Solution Present Yet

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# Quiz
1
Discuss

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

  • 1] a
  • 2] b
  • 3] c
  • 4] All equal
Solution
2
Discuss

Simplify : \(\frac{{ - \frac{1}{2} - \frac{2}{3} + \frac{4}{5} - \frac{1}{3} + \frac{1}{5} + \frac{3}{4}}}{{\frac{1}{2} + \frac{2}{3} - \frac{4}{3} + \frac{1}{3} - \frac{1}{5} - \frac{4}{5}}}\)

 

  • 1]

    -3/10

  • 2]

    -10/3

  • 3]

    -2

  • 4]

    1

Solution
3
Discuss

Simplify : \(\root 3 \of { - 2197} \,\times \)  \(\root 3 \of { - 125} \,\,\div \)   \(\root 3 \of {\frac{{27}}{{512}}} \)  = ?

 

  • 1]

    \(\frac{{492}}{7}\)

  • 2]

    \(\frac{{520}}{3}\)

  • 3]

    \(\frac{{554}}{7}\)

  • 4]

    \(\frac{{571}}{5}\)

Solution
4
Discuss

Simplification of \(\frac{{{{\left( {3.4567} \right)}^2} - {{\left( {3.4533} \right)}^2}}}{{0.0034}} = ?\)

 

  • 1] 6.91
  • 2] 7
  • 3] 6.81
  • 4] 7.1
Solution
5
Discuss

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

 

  • 1] ± 2
  • 2] 1, 2
  • 3] 2, 3
  • 4] ± 1
Solution
6
Discuss

If \(\frac{a}{b}{ \text{ + }}\frac{b}{a}{ \text{ = 2,}}\)    then the value of (a - b) is = ?

 

  • 1] 1
  • 2] 2
  • 3] -1
  • 4] 0
Solution
7
Discuss

64^12 / 4^15 = 64^x

  • 1]

    6

  • 2]

    5

  • 3]

    4

  • 4]

    7

Solution
8
Discuss

If 37/13 =   where x,y,z are natural member , then find x+y+z are:-

  • 1]

    6

  • 2]

    7

  • 3]

    8

  • 4]

    9

Solution
9
Discuss

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

 

  • 1] -1
  • 2] 0
  • 3] 1
  • 4] None of these
Solution
10
Discuss

Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times  2\sqrt {3\frac{1}{9}}\)   = ?

 

  • 1]

    45/256

  • 2]

    \(1\frac{{17}}{{28}}\)

  • 3]

    \(4\frac{3}{8}\)

  • 4]

    \(2\frac{3}{{16}}\)

Solution
# Quiz