Quiz Discussion

(4/9) × 1701 + (2/11) × 1386 = ?

Course Name: Quantitative Aptitude

  • 1]

    180

  • 2]

    1080

  • 3]

    1008

  • 4]

    1800

Solution
No Solution Present Yet

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# Quiz
1
Discuss

64^12 / 4^15 = 64^x

  • 1]

    6

  • 2]

    5

  • 3]

    4

  • 4]

    7

Solution
2
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
3
Discuss

\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)

 

  • 1]

    2/5

  • 2]

    5/2

  • 3]

    3/5

  • 4]

    1/2

Solution
4
Discuss

Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)

 

  • 1]

    \(8\frac{1}{5}\)

  • 2]

    \(9\frac{1}{2}\)

  • 3]

    \(11\frac{1}{2}\)

  • 4]

    \(10\frac{3}{5}\)

  • 5]

    \(12\frac{1}{5}\)

Solution
5
Discuss

\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)

 

  • 1] 0.1
  • 2] 10
  • 3] 102
  • 4] 103
Solution
6
Discuss

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

 

  • 1] 5√5
  • 2] (125)2
  • 3] 25
  • 4] 5
  • 5] None of these
Solution
7
Discuss

\(\frac{{{{\left( {469 + 174} \right)}^2} - {{\left( {469 - 174} \right)}^2}}}{{469 \times 174}} \)      = ?

 

  • 1] 2
  • 2] 4
  • 3] 295
  • 4] 643
Solution
8
Discuss

Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times  2\sqrt {3\frac{1}{9}}\)   = ?

 

  • 1]

    45/256

  • 2]

    \(1\frac{{17}}{{28}}\)

  • 3]

    \(4\frac{3}{8}\)

  • 4]

    \(2\frac{3}{{16}}\)

Solution
9
Discuss

(36.14)^2 – (21.28)^2 =?

  • 1]

    850

  • 2]

    860

  • 3]

    865

  • 4]

    853

Solution
10
Discuss

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

 

  • 1]

    \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

  • 2]

    \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

  • 3]

    \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

  • 4]

    \(\frac{{{a^2} - {b^2}}}{{ab}}\)

Solution
# Quiz