Quiz Discussion

The expression \(\frac{1}{{x - 1}} - \frac{1}{{x + 1}} - \frac{2}{{{x^2} + 1}} - \frac{4}{{{x^4} + 1}}\)  is equal to = ?

• 1]

  \(\frac{8}{{{x^8} + 1}}\)

• 2]

  \(\frac{8}{{{x^8} - 1}}\)

• 3]

  \(\frac{8}{{{x^7} - 1}}\)

• 4]

  \(\frac{8}{{{x^7} + 1}}\)

The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?

• 1] Rs. 1200
• 2] Rs. 2400
• 3] Rs. 4800
• 4] Cannot be determined
• 5] None of these

\(1888 \div 32 \div 8 = ?\)

• 1] 7.375
• 2] 9.485
• 3] 29.5
• 4] 472
• 5] None of these

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

• 1] a - b
• 2] b - a
• 3] 1
• 4] 0

A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:

• 1] 22
• 2] 23
• 3] 24
• 4] 26

If 45 - [28 - {37 - (15 - *)}]  then * equal to?

• 1] -29
• 2] -19
• 3] 19
• 4] 29

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)