Quiz Discussion

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

If 37/13 =   where x,y,z are natural member , then find x+y+z are:-

• 1]

  6

• 2]

  7

• 3]

  8

• 4]

  9

The value of \(\frac{5}{{1\frac{7}{8}{ \text{of 1}}\frac{1}{3}}} \times \frac{{2\frac{1}{{10}}}}{{3\frac{1}{2}}}{ \text{ of 1}}\frac{1}{4} = ?\)

• 1]

  \(1\frac{1}{2}\)

• 2]

  0.05

• 3]

  1

• 4]

  2

One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?

• 1] Rs. 30,000
• 2] Rs. 50,000
• 3] Rs. 60,000
• 4] Rs. 90,000
• 5] None of these

\(\frac{3}{7}{ \text{of }} 455 + \frac{5}{8}{ \text{of}}456 = ?\)

• 1] 448
• 2] 464
• 3] 476
• 4] 480
• 5] None of these

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)

• 1]

  2/5

• 2]

  5/2

• 3]

  3/5

• 4]

  1/2

A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?

• 1] 1500
• 2] 1600
• 3] 1800
• 4] 2400

What number must be added to the expression 16a2 - 12a to make a perfect square ?

• 1]

  9/4

• 2]

  11/2

• 3]

  13/2

• 4]

  16

The expression \(\frac{1}{{x - 1}} - \frac{1}{{x + 1}} - \frac{2}{{{x^2} + 1}} - \frac{4}{{{x^4} + 1}}\)  is equal to = ?

• 1]

  \(\frac{8}{{{x^8} + 1}}\)

• 2]

  \(\frac{8}{{{x^8} - 1}}\)

• 3]

  \(\frac{8}{{{x^7} - 1}}\)

• 4]

  \(\frac{8}{{{x^7} + 1}}\)