\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\) Find the value in place of (?)
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Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)
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If x + y = 2a, then the value of
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If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\) then \(\left( {x - \frac{1}{x}} \right)\) is equal to = ?
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The simplified value of
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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The least number that must be subtracted from 63522 to make the result a perfect square is = ?
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64^12 / 4^15 = 64^x
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If \(\left( {a + \frac{1}{a}} \right) = 6, then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\) = ?
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Solve : 128.43 + 30.21 + ? = 173
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If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\) is = ?
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