Quiz Discussion

By what least number 4320 be multiplied to obtain a number which is a perfect cube?

• 1]

  35

• 2]

  48

• 3]

  50

• 4]

  62

\(\sqrt {\frac{{25}}{{81}} - \frac{1}{9}} = ?\)

• 1]

  2/3

• 2]

  4/9

• 3]

  16/81

• 4]

  25/81

Find the cube root of 2744.

• 1]

  14

• 2]

  13

• 3]

  12

• 4]

  11

Determined the value of \(\frac{1}{{\sqrt 1 + \sqrt 2 }}{ \text{ + }}  \frac{1}{{\sqrt 2 + \sqrt 3 }} +   \frac{1}{{\sqrt 3 + \sqrt 4 }} +   ...... +   \frac{1}{{\sqrt {120} + \sqrt {121} }}{ \text{ = ?}}\)

• 1]

  8

• 2]

  10

• 3]

  \(\sqrt {120} \)

• 4]

  \(12\sqrt 2 \)

A mobile company offered to pay the Indian Cricket Team as much money per run scored by the side as the total number it gets in a one-dayer against Australia. Which one of the following cannot be the total amount to be spent by the company in this deal ?

• 1] 21904
• 2] 56169
• 3] 101761
• 4] 121108

If \(\sqrt {24} = 4.889,\)   the value of \(\sqrt {\frac{8}{3}} \)   is = ?

• 1] 0.544
• 2] 1.333
• 3] 1.633
• 4] 2.666

\(\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right){\kern 1pt} \)     is equal to :

• 1] 5
• 2] 6
• 3] 8
• 4] 11

If \(x = 3 + \sqrt 8 ,   \) then \({x^2} + \frac{1}{{{x^2}}}\) is equal to = ?

• 1] 30
• 2] 34
• 3] 36
• 4] 38

\({\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\) simplifies to:

• 1]

  3/4

• 2]

  \(\frac{4}{{\sqrt 3 }}\)

• 3]

  4/3

• 4]

  None of these

The value of \(\sqrt {0.01} { \text{ + }} \sqrt {0.81} { \text{ + }} \sqrt {1.21} { \text{ + }} \sqrt {0.0009} \)  is = ?

• 1] 2.03
• 2] 2.1
• 3] 2.11
• 4] 2.13