Quiz Discussion

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

Course Name: Quantitative Aptitude

  • 1] 770
  • 2] 1155
  • 3] 1540
  • 4] (385)2
Solution
No Solution Present Yet

Top 5 Similar Quiz - Based On AI&ML

Quiz Recommendation System API Link - https://fresherbell-quiz-api.herokuapp.com/fresherbell_quiz_api

# Quiz
1
Discuss

Evaluated : \({{9\left| {3 - 5} \right| - 5\left| 4 \right| \div 10} \over { - 3\left( 5 \right) - 2 \times 4 \div 2}}\)

 

  • 1]

    9/10

  • 2]

    -8/17

  • 3]

    -16/19

  • 4]

    4/7

Solution
2
Discuss

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

 

  • 1] 5√5
  • 2] (125)2
  • 3] 25
  • 4] 5
  • 5] None of these
Solution
3
Discuss

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

 

  • 1]

    \(17\frac{5}{{12}}\)

  • 2]

    \(17\frac{8}{{17}}\)

  • 3]

    \(20\frac{3}{{25}}\)

  • 4]

    \(20\frac{{103}}{{250}}\)

Solution
4
Discuss

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

 

  • 1]

    1

  • 2]

    \(\frac{{x + y + z}}{{a + b + c}}\)

  • 3]

    \(\frac{{a + b + c}}{{x + y + z}}\)

  • 4]

    Not possible to find

Solution
5
Discuss

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

 

  • 1] 0
  • 2] 1
  • 3] 2
  • 4] 5
Solution
6
Discuss

\(1888 \div 32 \div 8 = ?\)

 

  • 1] 7.375
  • 2] 9.485
  • 3] 29.5
  • 4] 472
  • 5] None of these
Solution
7
Discuss

(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?

  • 1]

    5.5

  • 2]

    4.0

  • 3]

    4.5

  • 4]

    3.0

Solution
8
Discuss

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

 

  • 1] 0
  • 2] 1
  • 3] 2
  • 4] 5
Solution
9
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
10
Discuss

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

 

  • 1]

    10/3

  • 2]

    82/9

  • 3]

    7

  • 4]

    11

Solution
# Quiz