Quiz Discussion

The square root of \(\frac{{0.342 \times 0.684}}{{0.000342 \times 0.000171}} = ?\)

• 1] 250
• 2] 2500
• 3] 2000
• 4] 4000

5907 – 1296 / 144 = x * 8.0

• 1]

  700.05

• 2]

  705.25

• 3]

  751.54

• 4]

  737.25

The simplest value of \(\left( {\frac{1}{{\sqrt 9 - \sqrt 8 }} - \frac{1}{{\sqrt 8 - \sqrt 7 }} + \frac{1}{{\sqrt 7 - \sqrt 6 }} - \frac{1}{{\sqrt 6 - \sqrt 5 }}} \right)\)          is = ?

• 1]

  \(3 - \sqrt 5 \)

• 2]

  3

• 3]

  \(\sqrt 5 \)

• 4]

  \(\sqrt 5 - 3\)

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

• 1]

  40.019

• 2]

  35.055

• 3]

  37.514

• 4]

  38.399

\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)

• 1]

  2/5

• 2]

  5/2

• 3]

  3/5

• 4]

  1/2

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

• 1]

  1/2

• 2]

  4

• 3]

  2

• 4]

  1/4

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)

• 1]

  \(8\frac{1}{5}\)

• 2]

  \(9\frac{1}{2}\)

• 3]

  \(11\frac{1}{2}\)

• 4]

  \(10\frac{3}{5}\)

• 5]

  \(12\frac{1}{5}\)

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

• 1] 3, 1
• 2] 3, 3
• 3] 4, 1
• 4] 5, 3

Simplify : \(\root 3 \of { - 2197} \,\times \)  \(\root 3 \of { - 125} \,\,\div \)   \(\root 3 \of {\frac{{27}}{{512}}} \)  = ?

• 1]

  \(\frac{{492}}{7}\)

• 2]

  \(\frac{{520}}{3}\)

• 3]

  \(\frac{{554}}{7}\)

• 4]

  \(\frac{{571}}{5}\)