Quiz Discussion

Let 0 < x < 1, then the correct inequality is = ?

• 1]

  \(x < \sqrt x < {x^2}\)

• 2]

  \(\sqrt x < x < {x^2}\)

• 3]

  \({x^2} < x < \sqrt x \)

• 4]

  \(\sqrt x < {x^2} < x\)

The least number that must be subtracted from 63522 to make the result a perfect square is = ?

• 1] 18
• 2] 20
• 3] 24
• 4] 30

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\)  \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

• 1] 40 minutes
• 2] 45 minutes
• 3] 48 minutes
• 4] 36 minutes

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

Simplification of \(\frac{{{{\left( {3.4567} \right)}^2} - {{\left( {3.4533} \right)}^2}}}{{0.0034}} = ?\)

• 1] 6.91
• 2] 7
• 3] 6.81
• 4] 7.1

\(1888 \div 32 \div 8 = ?\)

• 1] 7.375
• 2] 9.485
• 3] 29.5
• 4] 472
• 5] None of these

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

• 1]

  5/16

• 2]

  6/19

• 3]

  18/5

• 4]

  24/11

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

• 1]

  10/3

• 2]

  82/9

• 3]

  7

• 4]

  11

Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)

• 1]

  100/101

• 2]

  90/101

• 3]

  20/101

• 4]

  101/100