Quiz Discussion

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

• 1] 770
• 2] 1155
• 3] 1540
• 4] (385)2

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

• 1]

  0

• 2]

  1

• 3]

  \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

• 4]

  \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

(? - 968) / 79 * 4 = 512

• 1] 10185
• 2] 10190
• 3] 11075
• 4] 11080
• 5] None of these

421 ÷ 35 × 299.97 ÷ 25.05 = ?2

• 1] 22
• 2] 24
• 3] 28
• 4] 12
• 5] 18

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

• 1]

  10/3

• 2]

  82/9

• 3]

  7

• 4]

  11

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

• 1] a - b
• 2] b - a
• 3] 1
• 4] 0

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

• 1] -1
• 2] 0
• 3] 1
• 4] None of these

572.0 / 26 * 12 – 200 = (2)^x

• 1]

  8

• 2]

  4

• 3]

  6

• 4]

  10