Quiz Discussion

\(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} + \frac{1}{{14}} + \frac{1}{{28}}\)     is equal to = ?

• 1] 2
• 2] 2.5
• 3] 3
• 4] 3.5

Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\)  = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\)  + \(\sqrt {0.013}\)

• 1] 36.164
• 2] 36.304
• 3] 37.304
• 4] 37.164

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these

Evaluate : \(\frac{{\left( {923 - 347} \right)}}{?} = 32\)

• 1] 35
• 2] 20
• 3] 18
• 4] 15
• 5] 40

Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)

• 1]

  0.006

• 2]

  1/6

• 3]

  0.6

• 4]

  6

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

• 1]

  6/49

• 2]

  6/11

• 3]

  3/28

• 4]

  1/7

• 5]

  None of these

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

• 1]

  \({x^6} - \frac{1}{{{x^6}}}\)

• 2]

  \({x^8} - \frac{1}{{{x^8}}}\)

• 3]

  \({x^6} + \frac{1}{{{x^6}}}\)

• 4]

  \({x^8} + \frac{1}{{{x^8}}}\)

If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)

• 1]

  10/9

• 2]

  1/9

• 3]

  11/7

• 4]

  8/7

Solve : 128.43 + 30.21 + ? = 173

• 1] 35.66
• 2] 29.66
• 3] 43.66
• 4] 24.66
• 5] 14.36