Quiz Discussion

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

• 1] ± 2
• 2] 1, 2
• 3] 2, 3
• 4] ± 1

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

• 1] 770
• 2] 1155
• 3] 1540
• 4] (385)2

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

421 ÷ 35 × 299.97 ÷ 25.05 = ?2

• 1] 22
• 2] 24
• 3] 28
• 4] 12
• 5] 18

If 45 - [28 - {37 - (15 - *)}]  then * equal to?

• 1] -29
• 2] -19
• 3] 19
• 4] 29

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

• 1]

  \(1\frac{{11}}{{17}}\)

• 2]

  \(1\frac{{5}}{{7}}\)

• 3]

  \(1\frac{{6}}{{17}}\)

• 4]

  \(1\frac{{21}}{{17}}\)

Simplify : \(\root 3 \of { - 2197} \,\times \)  \(\root 3 \of { - 125} \,\,\div \)   \(\root 3 \of {\frac{{27}}{{512}}} \)  = ?

• 1]

  \(\frac{{492}}{7}\)

• 2]

  \(\frac{{520}}{3}\)

• 3]

  \(\frac{{554}}{7}\)

• 4]

  \(\frac{{571}}{5}\)