Quiz Discussion

R is a positive number. It is multiplied by 8 and then squared. The square is now divided by 4 and the square root is taken. The result of the square root is Q. What is the value of Q ?

• 1] 3R
• 2] 4R
• 3] 7R
• 4] 9R

If y = 5,   then what is the value of \(10y\sqrt {{y^3} - {y^2}} \)   = ?

• 1]

  \(50\sqrt 2 \)

• 2]

  100

• 3]

  \(200\sqrt 5 \)

• 4]

  500

If \(a = \frac{{\sqrt 3 + \sqrt 2 }}{{\sqrt 3 - \sqrt 2 }},   b = \frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt 3 + \sqrt 2 }}\)   then the value of \({a^2} + {b^2}\)   would be = ?

• 1] 10
• 2] 98
• 3] 99
• 4] 100

\(\sqrt {1.5625} = ?\)

• 1] 1.05
• 2] 1.25
• 3] 1.45
• 4] 1.55

Which of the following is closest to \(\sqrt 3 = ?\)

• 1]

  1.69

• 2]

  173/100

• 3]

  1.75

• 4]

  9/5

Given \(\sqrt 2 = 1.414.\)   Then the value of \(\sqrt 8\)  + \(2\sqrt {32} \)  -  \(3\sqrt {128}\)  + \(4\sqrt {50}\)   is = ?

• 1] 8.426
• 2] 8.484
• 3] 8.526
• 4] 8.876

What should come in place of both the question marks in the equation x/√128 = √162/x ?

• 1] 12
• 2] 14
• 3] 144
• 4] 196

If \(x = \frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}}   \)  \(y = \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}\)and then the value of \(\left( {{x^2} + {y^2}} \right)\)   is?

• 1] 10
• 2] 13
• 3] 14
• 4] 15

\({\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\) simplifies to:

• 1]

  3/4

• 2]

  \(\frac{4}{{\sqrt 3 }}\)

• 3]

  4/3

• 4]

  None of these

If x=.and y= find value of  is

• 1]

  13

• 2]

  14

• 3]

  15

• 4]

  16