Quiz Discussion

If \(x = \frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}}   \)  \(y = \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}\)and then the value of \(\left( {{x^2} + {y^2}} \right)\)   is?

• 1] 10
• 2] 13
• 3] 14
• 4] 15

\(\left( {\frac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }} + \frac{{2 - \sqrt 3 }}{{2 + \sqrt 3 }} + \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right) \)     simplifies to = ?

• 1]

  \(16 - \sqrt 3 \)

• 2]

  \(4 - \sqrt 3 \)

• 3]

  \(2 - \sqrt 3 \)

• 4]

  \(2 + \sqrt 3 \)

If \(\sqrt y = 4x{ \text{}}   \) then \(\frac{{{x^2}}}{y}\) is = ?

• 1]

  2

• 2]

  1/16

• 3]

  1/4

• 4]

  4

If x=.and y= find value of  is

• 1]

  13

• 2]

  14

• 3]

  15

• 4]

  16

By what least number 4320 be multiplied to obtain a number which is a perfect cube?

• 1]

  35

• 2]

  48

• 3]

  50

• 4]

  62

\(\sqrt ? \times \sqrt {484} = 1034\)

• 1] 2025
• 2] 2209
• 3] 2304
• 4] 2401
• 5] None of these

The square root of 64009 is:

• 1] 253
• 2] 347
• 3] 363
• 4] 803

Find the cube root of 2744.

• 1]

  14

• 2]

  13

• 3]

  12

• 4]

  11

\(\sqrt {\frac{{16}}{{25}}} \times \sqrt {\frac{?}{{25}}} \times \frac{{16}}{{25}} = \frac{{256}}{{625}}\)

• 1] 5
• 2] 8
• 3] 16
• 4] None of these

\( \root 3 \of {\sqrt {0.000064} } = ?\)

• 1] 0.02
• 2] 0.2
• 3] 2
• 4] None of these